Question

In a single experiment, a die is tossed and a spinner with the letters A, B, and C is spun. Each letter is equally likely. Find the sample space and then find the probability of getting a B.
a.
The sample space is 18. The probability of getting a B is 1/9
b.
The sample space is 18. The probability of getting a B is 1/3
c.
The sample space is 9. The probability of getting a B is 1/9
d.
The sample space is 9. The probability of getting a B is 1/18

Answer 1

The answer is:C hope it is correct

Answer 2

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

A die is tossed and a spinner with letters A, B and C.

Number of letters in a spinner = 3

Number of outcomes in a die = 6

Each letter is equally likely occurred.

So, the number of elements in the sample space would be

$3\times 6=18$

Sample space would be

{1A,2A,3A,4A,5A,6A,1B,2B,3B,4B,5B,6B,1C,2C,3C,4C,5C,6C}

Number of outcomes of getting B = 6

So, Probability of getting B would be $\dfrac{6}{18}=\dfrac{1}{3}$

Hence, Option 'B ' is correct.