Answer: v = u= 
Step-by-step explanation:
v= cos45 * 4=
- Apply Pythagorean theorem
= 
We have u =
Answer:
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Class 9
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>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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The new width is 16.6666666667 inches, which can be rounded to 16.7.
Width: 5 ?
Height: 6 20
We know that based on the information provided, the new height is 20 inches.
So, in order to solve, you can cross multiply (5 x 20), which would be 100. Then
divide by 6, to get 16.6666666667 or 16.7.
4 + 5t < 19
Subtract 4 from both sides
5t < 19 - 4 or 5t < 15
Divide both sides by 5
t < 3
Answer:
y = 4/5x + 2
Step-by-step explanation:
Standard equation given slope and y-intercept -> y = mx + b
After substituting variables m and b, you get y = 4/5x + 2.
