On hypotenuse of the triangle .
Right bisectors of the sides of a right triangle triangle meet hypotenuse.
To solve this, first we'll find the area of the rectangle A,
Area=length × width
?=24m×20m
480m=24m×20m
480m squared=area of the rectangle A
now we'll find the width of rectangle B,
"the width of rectangle B is 12 meters less than the width of rectangle A",
20m-12m= 8m
8m=width of rectangle B
finally we'll find the length of rectangle B,
area of the rectangle B= 480msquared
width= 8m
length=? (to find this divide the area by the width)
480÷8=60m
length of the rectangle B=60m
Answer:
We know that the figure has a symmetry
angle 1 = angle 2
angle 1 =180°-(18°+90°) = 180° - 108°=72°
Therefore, <em><u>angle 2 =72°</u></em><em><u>.</u></em>
Answer:
3.3
Step-by-step explanation:
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