The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the inequality:
3 ≤ |x + 2| ≤ 6
Hence:
x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)
This gives:
x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
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Answer:
B. Subtract the bottom equation from the top equation.
Step-by-step explanation:
When looking at the two equations:
8x + 8y = 2
8x + 5y = 1
We can easily get rid of the x variable by subtracting the two equations from each other since the terms are equivalent. This would allow us to solve for the y value, which we could plug into the an equation to solve for the x value.
Answer:
y = 0x + 70
y = 4x + 15
y = 6x + 0
Step-by-step explanation:
Answer:
of the game is left.
Step-by-step explanation:
A hockey game has 3 periods.
Now, it is halfway through two periods, which means that 2 + 0.5 = 2.5 periods have been played.
Amount remaining:
Total of 100% = 1, subtracted by the fraction played, which is 2.5 of 3 = 5 of 6. So
of the game is left.
We are given the following problem
As you can see, the negative sign is being multiplied with a negative sign.
Recall that when a negative sign is multiplied with a negative sign then the result is a positive sign.
Therefore, the result is positive 10
