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3 years ago

24/40 in simplest for PLEASE HELP!!!!!!

2 answers:

7 0

Hey there!

24/40 in simplest form is 3/5

All you have to do is see what number can go in to each of them evenly, and is the highest one, so for this it is 8.

Hope I was able to help!

mash [69]3 years ago

5 0

24/40 = (4x6) / (4x10) = 6/10 =3/5

You might be interested in

A x b = 400 a ÷ b = 4 how much is b

laila [671]

Answer:

4 x 100 = 400

400 ÷100 = 4

B= 100

Step-by-step explanation:

8 0

3 years ago

Goran made 6 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 6 necklaces

Tema [17]

  6b + 6p = 33.60 ; b=2.90

6(2.90) + 6p = 33.60

17.40 + 6p = 33.60
-17.40 -17.40

  6p = 16.20
/6 /6

  p = 2.70

ANSWER: each pendant costs $2.70

5 0

3 years ago

he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w

stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666 )

Step-by-step explanation:

Given the data in the question;

Sample 1 Sample 2

x"₁ = 259.23 x"₂ = 365.12

s₁ = 34.713 s₂ = 48.297

n₁ = 5 n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

$S_p^2$ = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

$S_p^2$ = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

$S_p^2$ = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [ 4 + 9 ]

$S_p^2$ = [ 4819.9692 + 20993.4 ] / [ 13 ]

$S_p^2$ = 25813.3692 / 13

$S_p^2$ = 1985.64378

Now the Standard Error will be;

$S_{x1-x2$ = √[ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

$S_{x1-x2$ = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

$S_{x1-x2$ = √[ 397.128756 + 198.564378 ]

$S_{x1-x2$ = √595.693134

$S_{x1-x2$ = 24.4068

Critical Value = $t_{\frac{\alpha }{2}, df$ = $t_{0.05, df=13$ = 1.771 { t-table }

So,

Margin of Error E = $t_{\frac{\alpha }{2}, df$ × [ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666 )

3 0

3 years ago

Hi there! Can someone help me with this, i need a proper answer, i don't need LINKS or FILES for the explanations.

alexira [117]

Answer:

Using below system of inequalities

y > 2x - 3
y < x + 1

Following the rules

1. Finding x- and y - intercepts
2. Connecting with dotted line for each as no equal symbol present in any inequality
3. Shade respective regions
4. Solution is the intersection of the shades regions
5. Select any three points in the solution region

Line 1