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wariber [46]
3 years ago
12

Compound Probability: You choose a tile at random from a bag containing 2 tiles with X, 6 tiles with Y, and 4 tiles with Z. You

pick a second tile without replacing the first. Find each probability.18. P(X then Y) 19. (both Y) 20. P(Y then X) 21. (P(Z then X)22. P(both Z) 23. P(Y then Z)You don't have to answer all of them, I just want someone to solve like two and explain how they did it so I can do the rest on my own.
Mathematics
1 answer:
Schach [20]3 years ago
5 0
18. P(x then y) = 1/11
19. P(both y) = 5/22

To find the probability of these compound events, we have to multiply the probability of each individual event. Remember, on the second trial, there are only 11 options.

18.  2/12 x 6/11 = 1/11

19.  6/12 x 5/11 = 5/22
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Answer?......................
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22

Step-by-step explanation:

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7 0
2 years ago
The following normal account balances were found on the general ledger before closing entries were prepared: Revenue $800 Cash $
Virty [35]

Answer:

$ 7250

Step-by-step explanation:

Data provided:

Revenue = $800

Cash = $500

Expenses = $400

Accounts Receivable = $350

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Withdrawals = $1,000

Balance in the cash account

=(Revenue+Cash + Accounts Receivable + Capital )-(Expenses + Withdrawals)

on substituting the values, we get

Balance in cash account = ( $ 800 + $ 350 + $ 7,500 ) - ( $ 400 + $ 1,000)

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4 0
3 years ago
A stack of thirty cards is placed next to a ruler, and the height of stack is measured to be 3 /4 of an inch. How thick is one c
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You need to divide 3/4 inches by 30 cards.

Using the reciprocal rule,

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Multiplying fractions,
(3/4)*(1/30) = 3/120 = 1/40 inches.
4 0
3 years ago
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