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2 years ago

Answer?......................

Mathematics

1 answer:

erica [24]2 years ago

7 0

Answer:

Step-by-step explanation:

6( n^2 +2)

-----------------

Let n = 3

6( 3^2 +2)

-----------------

Parentheses first

6( 9 +2)

-----------------

6( 11)

-----------------

Top of the fraction next

-----

Divide

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The assumptions made are: The gas molecules from Caesar's last breath are now evenly dispersed in the atmosphere. The atmosphere

Dovator [93]

Answer:

$2.6\times 10^{19}m^{3}$

Step-by-step explanation:

we have given thickness of atmosphere =50 km

radius of earth =6400 km

average temperature of atmosphere=15°C

Average pressure of atmosphere= 0.20 atm

we have to calculate the volume of atmosphere

so the we have to calculate the volume of atmosphere = ( volume of earth +atmosphere) - volume of earth

volume of atmosphere = $\frac{4}{3}\times\pi \times \left ( 6400+50 \right )^{3}-\frac{4}{3}\times \pi\times 6400^3$

= $2.6\times 10^{19}m^{3}$

6 0

3 years ago

If x = 10, y = 5, and z = 11, what is the sine ratio for g°?

salantis [7]

Answer:

$\frac{10}{11}$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

In the right triangle ABC

$sin(g^o)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(g^o)=\frac{x}{z}$

$sin(g^o)=\frac{10}{11}$

8 0

3 years ago

Divide this polynomial:)

lutik1710 [3]

Answer:

The answer is 3x^2-4x-4+1/2x-1

Step-by-step explanation:

Hope this helps, and sorry if it's wrong.

8 0

3 years ago

Read 2 more answers

Which integer is √59 closer to

valentinak56 [21]

It is close to 8. When you look for the square root of 59 you should get about 7.6811457... Round up and thats 8 round down that 7 but it should be 8.

4 0

3 years ago

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The path of water from a hose on a fire tugboat can be approximated by the equation y=-0.0055x^2 +1.15x + 5, where y is the heig

Komok [63]

Answer:

The water is 208.22ft from the tug boat

Step-by-step explanation:

The governing equation is $y=-0.0055x^2 +1.15x + 5$

y is the height above the ocean

x is the distance from the tugboat

if y= 6ft, the equation will now become

$6=-0.0055x^2 +1.15x + 5$

we can arrange this properly to form a quadratic equation by grouping like terms.

$-0.0055x^2 +1.15x -1=0$

solving quadratically we have two values of x as 208.22ft and 0.873 ft.

We can take a more realistic value as a solution to our problems:

208.22ft

6 0

3 years ago