If they sell the same amount next year and want to reach $1,500, they must higher the price. to do that, they can divide the $1500 by the number of agendas. Do the math yourself, its not very hard.
<span>y - k = a(x - h)²
</span><span>y = (x − 5)² + 8 -------> y-8 = (x-5)²
</span>y - k = a(x - h)²
y - 8 = (x - 5)²
Compare these formulas we can see that k=8, h =5.
Vertex (5,8).
In An arithmetic sequence will add or subtract the same thing each time to find the next term. In this case we start with 10 and need to get to 40 on the 6th term. This is a difference of 30 that needs to be divided by 5 open spaces. You are adding 6 each time.
10, 16, 22, 28, 34, 40, _,_,_,_, 70, _,_,_,_,100,_,_,_, 124.
Another way to do this would be to look at the 5th term and multiply it by 4 to get to the 20th term. 34 x 4 = 124.
Answer:
The car will have lost it's total value by 2007.
Step-by-step explanation:
If initially the car was valued at 44,000$, and after 9 years it's value dropped to 15,000$, we can say that the car's value dropped in 29,000$. If we suppose that the drop is the same every year, we can say that it was of 3,222,2$ by each year.
This amount of money is the 7,3% of the initial value of the car (I multiplied 3,222,2 x 100 : 44,000).
a) The annual rate of change was of 7,3%.
b) There are 14 years between 1993 and 2007. If we multiply 7,3% by 14, we get that the car lost 102,2% of it's initial value.
