Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)} Whic
myrzilka [38]
(3,-6) because you can't have two of the same x's in a function
Choices A, C, D have a y-value that is 5 more than the x-value, so those points are on the line defined by the first equation.
Choice D satisfies the requirement
... y = 2x - 13
... 23 = 2·18 - 13
... 23 = 36 - 13
The appropriate choice is ...
... D (18, 23)
<h3>Answer-</h3>
I think 11 is the median for the data.
25% chance because there are 8 total “slices” and there are 2 A’s.
2/8=1/4=25%
Answer:
14, 48, 50
Step-by-step explanation:
To check which set of side length can be used to form a right triangle we use pythagorean theorem
c^2 = a^2 + b^2
biggest side (hypotenuse is c^2)
(a) 14, 48, 50
2500= 196+2304
2500= 2500 that is true
(b) 30, 40, 60
3600= 900+ 1600
3600= 2500 that is false
(c) 14, 50, 60
3600= 196+2500
2500= 2196 that is false
(d) 10, 24,28
784=100+576
784=676 that is false
