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Answer:
d) -4 ≤ x ≤ 1.5
Step-by-step explanation:
The domain is the horizontal extent of the graph. Here, it goes from about x=-4 to about x = 1.5.
There are solid dots on both ends of the line segment, so the inequality will use ≤ for both limits. The domain is ...
-4 ≤ x ≤ 1.5
Answer:
(x+4)(6x^2 - 7)
Step-by-step explanation:
Focus on the first 2 terms first and on the second 2 terms last:
6x^3 + 24x^2 = 6x^2(x+4)
-7x-28 = -7(x+4)
We see that the factor (x+4) is common to both pairs: common to the first 2 terms and common to the last 2 terms.
Thus,
6x³ + 24x² -7x -28 = (x+4)(6x^2 - 7(x+4)
Factoring out x+4, we get (6x^2 - 7), and so 6x³ + 24x² -7x -28 in factored form is (x+4)(6x^2 - 7).
<h3>
Answer: B) the function g(x) has a larger slope</h3>
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Explanation:
The slope of f(x) is 4, since the equation y = 4x+2 has slope m = 4. Compare this to y = mx+b.
The slope of g(x) is 5. Note how if we started at (0,-2) on the red line and moved up 5 and to the right 1, we arrive at (1,3) which is another point on the red line. You could use the slope formula
m = (y2-y1)/(x2-x1)
to get the same result.
Since the slope of f(x) is 4 and the slope of g(x) is 5, we see that g(x) has a larger slope. The g(x) line is steeper compared to f(x).
Given
We have to set the restraint
because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:
The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have
So, we have to impose
Squaring both sides, we have
The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.
