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katrin2010 [14]
4 years ago
5

The length and width of a rectangle are consecutive odd integers. The perimeter is 88 meters. Find the length and width.

Mathematics
1 answer:
victus00 [196]4 years ago
5 0

Answer:

A

Step-by-step explanation:

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Simplify.<br><br> −9x − 3 − (5x + 3) − 7
Ket [755]

Answer: I got -14x-13

But it sounds wrong but I have a picture

Step-by-step explanation:

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4 years ago
TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title
Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}

z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}

Then

\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}

In trigonometric form, this is

\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}

8 0
3 years ago
Can you use the ASA postulate or the ASA theorem to prove the triangles are congruent?
velikii [3]
Yeah you surely can use them by ASA only
7 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS QUESTION
Lubov Fominskaja [6]

Answer:

me dont know

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP!<br><br> What are the solutions to the equation ​2^−x = −2x?
topjm [15]
Plit the second term in 2{x}^{2}-x-12x​2​​ −x−1 into two terms2{x}^{2}+x-2x-1=02x​2​​ +x−2x−1=0
2 Factor out common terms in the first two terms, then in the last two termsx(2x+1)-(2x+1)=0x(2x+1)−(2x+1)=0
3 Factor out the common term 2x+12x+1(2x+1)(x-1)=0(2x+1)(x−1)=0
4 Solve for xxx=-\frac{1}{2},1x=−​2​​1​​ ,1



Decimal Form: -0.5, 1

6 0
3 years ago
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