7 see attached for work in the picture
A=-32 (acceleration is the constant g) integrating with respect to t
v=-32t+vi but initial velocity is equal to zero as it is just "dropped".
h=-32t^2/2+hi, since the initial height is 144 ft
h(t)=-16t^2+144
The object will be at the ground when h(t)=0
-16t^2+144
-16(t^2-9)=0
-16(t+3)(t-3)=0, but since we know t>0
t=3 seconds.
A is true. Thus D is also true. The result of the synthetic division shows C is true.
The appropriate choices are ...
A. (x - 2) is a factor of 3x² - 11x + 10
C. (3x² - 11x + 10) ÷ (x - 2) = (3x - 5)
D. The number 2 is a root of F(x) = 3x² - 11x + 10
√70 = 8.37
It would be between 8 and 9.
Answer:
2/15
Step-by-step explanation:
2/3 / 5/1 =
2/3 x 1/5 = 2/15
