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3 years ago

Evaluate the exponential expression (−2)6. Question 6 options: −12 12 −64 64

Mathematics

1 answer:

OlgaM077 [116]3 years ago

7 0

Answer:

Step-by-step explanation:

(-2) ^6

This is -2 multiplied by itself 6 times

-2 * -2 *-2 * -2* -2 *-2

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Find the sine ratio for ∠D. a. 7/25 b. 24/7 c. 25/24 d. 24/25

Shalnov [3]

Answer:

sin ∠D = 24/25

Step-by-step explanation:

sin = opposite / hypotenuse

Looking at ∠D, the opposite side is 24, hypotenuse is 25

Therefore sin = 24/25

8 0

2 years ago

Please help with geometry

Citrus2011 [14]

The answer is B.

172.0 in.²

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2 years ago

Explain why the expression 2y-y can be written as y

harina [27]

Answer:

2y is just 2 times y, so subtracted it would be 1y and 1y is just y.

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2 years ago

Read 2 more answers

Ms.Holmes decided to water her plants.She had 2 1/2 gallons of water.She gave each plant 1/4 gallon of water.Which expression co

Inessa [10]

Answer:

(1/4)x=2 1/2

Step-by-step explanation:

It is 2.5 gal. of water and 0.25 gal. of water per plant.

It could also be x=(1/4)/(2 1/2)

6 0

3 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0

3 years ago