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stiks02 [169]
4 years ago
10

Pleaseer❤️❤️ help me

Mathematics
1 answer:
defon4 years ago
8 0

Answer:

1)D 2)C 3)A 4)B 5) A

Step-by-step explanation:

1) The area rectangle is 36x^2 -1

We know ,

A= l*b

=36x^2 -1

=(6x)^2 -1

=(6x+1) (6x-2)

This the value of l,b respectively.

So, Perimeter of rectangle is 2(l+b)

P=2(6x+1) + 2(6x-1)

=24x

2)The area of square is 4(x+5)^2

We know,

A=l^2

=4(x+5)^2

=4(x^2 + 10x + 25)

=(2x+10)^2

This is the value of l=2x+10.

So, Perimeter of square is 4l

P=4(2x+10)

=8x+40

3)The fully factorized form is

= -2x^2 + 10x +12

= -2x^2 + 12x -2x +12

= -2x(x-6) -2(x-6)

= -2(x-6) (x+1)

4)The fully factorized form is

=x^4 -81

=(x^2)^2 -9^2

=(x^2 + 9) (x^2 - 9)

=(x^2 + 9) (x^2 - 3^2)

=(x^2 + 9) (x + 3) (x - 3)

5)The fully factorized form is

= 5x^4 - 320

= 5(x^4 - 64)

= 5((x^2)^2 - 8^2)

= 5(x^2 + 8) (x^2-8)

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Hunter-Best [27]
Hey there!

On this problem, we have to combine like terms. A like term in this sense doesn't have to have the same coefficient, but it has to have the same variable.

Our like terms are 2m and 4m, along with 3 and 5.

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Notice how 5 and three are like terms because they're both whole numbers and don't have any variables.

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3 years ago
PLZZZ ANSWERR 20 points Select correct answer
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Explanation
4 0
3 years ago
Read 2 more answers
Find the volume of the figure. Round your answer to the nearest tenth if necessary. Use 3.14 for T.
seraphim [82]

Answer:

\boxed{ \rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3} } \rm (rounded \: to \: nearest \: tenth)

Step-by-step explanation:

Given dimensions:

  • Radius of the cylinder = 7 metres
  • Height of the cylinder = 3 metres

Given value of π :

  • π = 3.14

To find:

  • The Volume of the cylinder

Solution:

Here, we'll need to use the formulae of the volume of cylinder,to find it's volume.Its actually like a savior while solving these type of questions.

\pink{\star}\boxed{\rm \: Volume_{(Cylinder)} = \pi{r} {}^{2} h}\pink{\star}

where,

  • π = 3.14
  • r² = (radius)²
  • h = height

Plug/substitute them onto the formulae,then simplify it using PEMDAS.

  • [We'll substitute the value of π later]

\rm \: Volume_{(Cylinder)} = \pi(7) {}^{2}  \times 3

\rm \: Volume_{(Cylinder)} = \pi(49)(3)

\rm \: Volume_{(Cylinder)} = 147\pi \:

  • Now substitute the value of π.

\rm \: Volume_{(Cylinder)} = 147 \times 3.14

\rm \: Volume_{(Cylinder)} = 461.58 \:  {m}^{3}

\boxed{\rm \: Volume_{(Cylinder)} \approx \: 461.6  \:  {m}^{3}} \rm (rounded \: to \: nearest \: tenth) \:

<u>Hence, we can conclude that:</u>

The volume of the cylinder is approximately

461.6 m³.

\rule{225pt}{2pt}

3 0
3 years ago
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