Answer:
y-3x=2......1
y=-2x-8 ......2
substituting value of y in equation 1
-2x-8-3x=2
-5x=2+8
x=10/-5=-2
substituting value of x in equation 1
y-3×(-2)=2
y+6=2
y=2-6=-4
x=-2
y=-4
(
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Answer:
(x, y) = (-5, -6)
Step-by-step explanation:
The coefficients of y are the same, so we can eliminate y by subtracting one equation from the other. Here, we choose to subtract the first from the second, so that the coefficient of x ends up positive.
(-5x +5y) -(-6x +5y) = (-5) -(0)
x = -5 . . . . . . simplify
-6(-5) +5y = 0 . . . . . . substitute x into the first equation
6 +y = 0 . . . . . . . . . . divide by 5
y = -6 . . . . . . subtract 6
The solution to the system of equations is (x, y) = (-5, -6).
Since you said men to women, there are 5 men in the dance recital and 6 women in the dance recital.
1. Look how the problem states. Ex: Ratio of men to women.
2. Look at the ratio. 5:48.
3. We know that there are 48 female performers at the dance recital.
So, there are 5 men at the dance recital.
Answer:
This type of study design is
Clinical Trial
Step-by-step explanation:
- It is clinical trial because in this study design a treatment is given to the individuals and then we observe this treatment. In this experiment, we are studying the effects by giving 500 mg of Vitamin and Placebo to the soldiers.
- It is not a cross-sectional study because this type of study is used to analyze characteristic of the population depending upon data but this study is not used for disease.
- It is also not a case-control study as well as prospective cohort study because case-control study is used to observe the new cases of a disease while prospective cohort study is used for determining risks or exposure factors of a disease.
- It is not a community trial as in which a community is under observation like a city or a country and it is also not a historical prospective cohort study because in this study type, we observe the cohorts (similar objects) with the different qualities. They are studied on the basis of these qualities.
Length of outer boundary =30m
So area of outer boundary =30×30
= 900m²
Length of inner boundary of path=30-1= 29m
Inner area =29×29 =841m²
So area of path is= outer area - inner area
=900- 841
= 59m²
