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Paul [167]
3 years ago
15

How do I do these questions?

Mathematics
1 answer:
DedPeter [7]3 years ago
5 0
I just did the first one but I don't know is it correct

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If the point A (6,9) is translated 4 units left, then find the new coordinates of the point A.
Alex_Xolod [135]

Answer:

(2, 9 )

Step-by-step explanation:

A translation of 4 units left is equivalent to subtracting 4 from the value of the x- coordinate, that is

(6, 9 ) → (6 - 4, 9 ) → (2, 9 )

6 0
3 years ago
I need help with this problemr-1.97=0.65
SpyIntel [72]
To figure out R, add 1.97+0.65 together. 1.97+.065=2.62
3 0
3 years ago
Which transformation will map an isosceles trapezoid onto itself? rotation by 180° about its center, reflection across a diagona
alukav5142 [94]

Answer:

The correct option is 4.

Step-by-step explanation:

The non parallel sides of an isosceles trapezoid are congruent.

The image of an isosceles trapezoid is same as the preimage of isosceles trapezoid if

1. Reflection across a line joining the midpoints of parallel sides.

2. Rotation by 360° about its center.

3. Rotation by 360° about origin.

If we rotate the trapezoid by 180° about its center, then the parallel sides will interchanged.

If we reflect the trapezoid across a diagonal, then the resultant figure will be a parallelogram.

If we reflect across a line joining the midpoints of the nonparallel sides, then the parallel sides will interchanged.

After rotation by 360° about the center, we always get an onto figure.

Therefore option 4 is correct.

6 0
3 years ago
Read 2 more answers
What time what equals 10
lions [1.4K]
5*2 = 10
10*1 = 10

Hope I helped
6 0
3 years ago
Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
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