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Serggg [28]
3 years ago
6

A package being delivered in the mail weighs 1056 ounces. How much does that package weigh in pounds?

Mathematics
1 answer:
Vlad1618 [11]3 years ago
5 0

Answer:

66

Step-by-step explanation:

16 oz equal a pound so 1056 divided by 16

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F(x) = 2x<br> g(x) = 2x + 1<br> Find<br> (f/g) (x) . Include ahy restrictions on the domain.
victus00 [196]

Answer:

quotient is 1 and remainder is -1

Step-by-step explanation:

\frac{f(x)}{g(x)}

_1_______________

2x+1 | 2x

- 2x + 1

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-1

7 0
3 years ago
ZB is 3x-5 BA is x+3
Akimi4 [234]
If B is the midpoint of ZA, then ZB = <span>BA
</span>3x-5 = <span>x+3
3x - x = 3 + 5
2x = 8
x = 8/2
x = 4

</span>ZA = ZB + BA
      =  3x-5 + x+3
      = 3*4 - 5 + 4 + 3
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Answer: <span>D. 14</span>
3 0
3 years ago
Guys I don’t know the answer tell me the remainder too
ikadub [295]

Answer:

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3 0
2 years ago
Read 2 more answers
A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of funds' returns shows an averag
Feliz [49]

A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is

A. 0.037773 to 0.202227

B. 3.7773% to 20.2227%

C. 59.98786% to 61.01214%

D. 51.7773% to 68.2227%

E. 10.988% to 13.012%

Answer: E. 10.988% to 13.012%

Step-by-step explanation:

Given;

Mean x= 12%

Standard deviation r = 4%

Number of samples tested n = 60

Confidence interval is 95%

Z' = t(0.025)= 1.96

Confidence interval = x +/- Z'(r/√n)

= 12% +/- 1.96(4%/√60)

= 12% +/- 0.01214%

Confidence interval= (10.988% to 13.012%)

3 0
3 years ago
A recent national survey indicated that 73 percent of respondents try to include locally grown foods in their diets. A 95 percen
lilavasa [31]

Answer:

Correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

Step-by-step explanation:

A hypothesis for the proportion of people who include locally grown foods in their diets can be defined as:

<em>H₀</em>: The proportion of people who include locally grown foods in their diets is <em>p</em>.

<em>Hₐ</em>: The proportion of people who include locally grown foods in their diets is difference from <em>p</em>.

The decision rule can be based on the 95% confidence interval.

If the confidence interval consists the hypothetical value of the true proportion then the null hypothesis will be accepted or else the null hypothesis will be rejected.

The 95% confidence interval for the proportion of all people in the country who try to include locally grown foods in their diets is given as (0.70, 0.76).

This interval implies that there is 0.95 probability that the true proportion of people who include locally grown foods in their diets is between 70% and 76%.

Assuming that the claim made was supported by the 95% confidence interval.

The claim should be:

Less than 75% of all people in the country try to include locally grown foods in their diets.

Because the 95% confidence interval defines the range of the true proportion as 70% to 76%. Most of the values are below 75%.

Thus, the correct option is:

"Less than 75% of all people in the country try to include locally grown foods in their diets."

3 0
3 years ago
Read 2 more answers
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