1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastaziya [24]
4 years ago
14

How to turn 8/20 into a percent

Mathematics
2 answers:
umka2103 [35]4 years ago
5 0
Percent means per 100. Set up a proportion like so.

8/20= x/100
20*5=188
8*5=40

40=x

Final answer: 40%
Katarina [22]4 years ago
3 0
<span>8/20 * 100 = 0.4 * 100 = 40% </span>
You might be interested in
Help asap please!! thank you
Pavlova-9 [17]

Answer: The third option

Step-by-step explanation:

(6) (5) is the area of the quadrilateral, therefore you subtract that value by the area of the semi-circle.

to find the area of a semi circle the formula is: (1/2) π ( r^{2})

The radius is 2.5 because the diameter is 5, and the radius is half the diameter.

6 0
3 years ago
Can you define f(0, 0) = c for some c that extends f(x, y) to be continuous at (0, 0)? If so, for what value of c? If not, expla
Ahat [919]

(i) Yes. Simplify f(x,y).

\displaystyle \frac{x^2 - x^2y^2 + y^2}{x^2 + y^2} = 1 - \frac{x^2y^2}{x^2 + y^2}

Now compute the limit by converting to polar coordinates.

\displaystyle \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = \lim_{r\to0} \frac{r^4 \cos^2(\theta) \sin^2(\theta)}{r^2} = 0

This tells us

\displaystyle \lim_{(x,y)\to(0,0)} f(x,y) = 1

so we can define f(0,0)=1 to make the function continuous at the origin.

Alternatively, we have

\dfrac{x^2y^2}{x^2+y^2} \le \dfrac{x^4 + 2x^2y^2 + y^4}{x^2 + y^2} = \dfrac{(x^2+y^2)^2}{x^2+y^2} = x^2 + y^2

and

\dfrac{x^2y^2}{x^2+y^2} \ge 0 \ge -x^2 - y^2

Now,

\displaystyle \lim_{(x,y)\to(0,0)} -(x^2+y^2) = 0

\displaystyle \lim_{(x,y)\to(0,0)} (x^2+y^2) = 0

so by the squeeze theorem,

\displaystyle 0 \le \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} \le 0 \implies \lim_{(x,y)\to(0,0)} \frac{x^2y^2}{x^2+y^2} = 0

and f(x,y) approaches 1 as we approach the origin.

(ii) No. Expand the fraction.

\displaystyle \frac{x^2 + y^3}{xy} = \frac xy + \frac{y^2}x

f(0,y) and f(x,0) are undefined, so there is no way to make f(x,y) continuous at (0, 0).

(iii) No. Similarly,

\dfrac{x^2 + y}y = \dfrac{x^2}y + 1

is undefined when y=0.

5 0
2 years ago
Using the graph , determine the coordinates of the vertex of the parabola
aivan3 [116]

Answer:

(-4,-4)

Step-by-step explanation:

Delta math

3 0
3 years ago
Will mark Branliest! Need help ASAP
Neko [114]

Answer:

12/2

Step-by-step explanation:

An integer is neither a fraction nor a decimal, but in this case you can simplify 12/2 to 6 which is a whole number making it an integer. Hope you found this helpful!

8 0
3 years ago
Read 2 more answers
How do you know when to add numbers? what is the sign rule
VARVARA [1.3K]

The most familiar case is that where you see a " + " sign between two numbers; that's an indication to add the two numbers (or terms) together.

Also, the instruction, "sum up the following," is a command to find the sum of all the numbers that follow.


8 0
3 years ago
Other questions:
  • How to use base ten blocks to divide
    12·2 answers
  • if a solid piece of naphthalene is heated and remains at 80c until it is compleatly melted you know that 80 c is
    11·1 answer
  • In the school band 6 over 24 of the members play the trumpet and simplest form where fraction of the band play the trumpet
    5·2 answers
  • Studies on a bottle-filling machine indicate that it fills bottles to a mean of 16 ounces with a standard deviation of 0.10 ounc
    8·1 answer
  • Find the additive inverse of -7+5i
    6·1 answer
  • Order each set of values from least to greatest 0.4 and 5/8 and 38%
    8·2 answers
  • If x2 = 64and y2 = 121, what is the value of x - y
    13·1 answer
  • Pease answer number 9 for me.
    6·1 answer
  • 1/2a + 5(3a + 3/2<br><br> Please help
    6·1 answer
  • What is the y-intercept of y = -32x - 2?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!