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Lera25 [3.4K]
3 years ago
5

What is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Mathematics
2 answers:
Natalija [7]3 years ago
7 0

Answer: Choice D) 8 & 1/8

This is read as "Eight and one-eighth"

======================================================

You want the perimeter so you'll add the three fractions to add up the three side lengths.

1/2 is the same as 4/8 (since 4 is half of 8). You can think of having a cake that is cut up into 8 equal slices. If you take 4 of those slices, then you take half of the cake.

So the value 3&1/2 is the same as 3&4/8. Similarly, 2&1/2 is equivalent to 2&4/8

We want to add the three mixed numbers: 2&1/8, 3&4/8, 2&4/8

Add up the fractional parts: 1/8+4/8+4/8 = (1+4+4)/8 = 9/8 = 1&1/8

The whole part '1' carries over to the other whole parts.

Add up the whole parts: 2+3+2 = 7

Then add in the carry: 7+1 = 8

Overall, the three numbers {2&1/8, 3&4/8, 2&4/8} add up to 8&1/8 which is the final answer (choice D)


Alex787 [66]3 years ago
3 0
Hi!
A is the answer:⏬⏬⏬⏬⏬⏬⏬⏬

The distance around a triangle, better noun as de "perimeter of a triangle"

is the total distance around the outside, which can be found by adding together the length of each side.

Perimeter (P) = Length A + Length B + Lenght C

In this case, we know that each side measure 2 \frac{1}{8}81​ feet, 3 \frac{1}{2}21​ feet, and 2 \frac{1}{2}21​feet  but we have to rewrite each one of this mixed fractions as improper fractions:

2 \frac{1}{8}81​ = \frac{16 + 1}{8}816+1​ = \frac{17}{8}817​   

3 \frac{1}{2}21​ = \frac{6 + 1}{2}26+1​ = \frac{7}{2}27​

2 \frac{1}{2}21​ = \frac{4 + 1}{2}24+1​ = \frac{5}{2}25​

Then we just add all of them to find the perimeter:

 = \frac{17 + 28 + 20}{8}817+28+20​ = \frac{65}{8}865​

A: The distance around a triangle is \frac{65}{8}865​feet
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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
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Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

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Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

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Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

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The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

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Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

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