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3 years ago

8

Plzzzzzzzz help me it’s urgent

1 answer:

zavuch27 [327]3 years ago

7 0

It should be A.
i know this because a proportion line is a straight line that travels through the origin.

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4. What’s the answer to this question?!

telo118 [61]

Answer:

2000

Step-by-step explanation:

3 0

3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

Y+7=-2(x-1)<br><br><br> hurry plz

zhannawk [14.2K]

Answer:

y=-2x-5

Step-by-step explanation:

First of all, you have to distribute -2 to (x-1) to get to this equation y+7=-2x+2. Then, you subtract 7 on both sides to get the slope-intercept of y = -2x - 5.

8 0

3 years ago

When inscribing a square in a circle, which of these should have equal lengths? A) a radius of the circle and a diagonal of the

koban [17]

Hope this helps you.

5 0

3 years ago

Read 2 more answers

Use the functions f(x) and g(x) to answer the question.

kenny6666 [7]

$f(x)=x^2+3\\\\g(x)=x-7\\\\(f+g)(x)=f(x)+g(x)=(x^2+3)+(x-7)=x^2+x-4$

Answer: C)

6 0

3 years ago