Answer:
Raise the power
Step-by-step explanation:
It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
<h3>How to prove a Line Segment?</h3>
We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.
Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.
In ΔPNM, ∠N = 90°
∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)
∠P + ∠M = 90°
Clearly, ∠M is an acute angle.
Thus; ∠M < ∠N
PN < PM (The side opposite to the smaller angle is smaller)
Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
Read more about Line segment at; brainly.com/question/2437195
#SPJ1
Answer:
48.45
Step-by-step explanation:
Answer:
x = $5.49 cost of the bananas
Step-by-step explanation:
x = cost of the bananas
$3.89 = cost of the peanut butter
$ 9.38 is the cost of both
Bananas + peanut butter = $9.38
x + $3.89 = $9.38
<u> - $ 3.89 = -$3.89 </u> Subtract $3.89 from both sides
x = $5.49