Answer:
1 x 3 x 1 = 3
Step-by-step explanation:
Hello,
any point equidistant from the ends of a segment belongs to the perpendicular bisector of the segment.
|AD|=|BD| and |AC|=|BC|
Plug in (7, 12) for x and y in the equation.
12 = 2(7) + 1
12 = 14 + 1
12 ≠ 15
Therefore, (7, 12) is not on the straight line equation.
I think 10,000 not sure though
Answer:
9
(z)
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