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lorasvet [3.4K]
4 years ago
7

A sofa costs $50 less than three times the cost of a chair. If the sofa and chair together cost $650, how much more does the sof

a cost than the chair?
A) $175
B) $225
C) $300
D) $475
Mathematics
2 answers:
Katarina [22]4 years ago
5 0

1. Let S represent the cost of the sofa and C represent the cost of the chair.

If the sofa costs $50 less than three times the cost of the chair, then effectively we can write this as:

S = 3C - 50

If the sofa and chair together cost $650, we can write this as:

S + C = 650

2. Now, we can find out how much the sofa and chair cost by solving the two equations we obtained above for C, and substituting S = 3C - 50 into S + C = 650. Thus, we get:

S + C = 650

if S = 3C - 50, then:

3C - 50 + C = 650

4C - 50 = 650 (Add C and 3C)

4C = 700 (Add 50 to both sides)

C = 175 (Divide both sides by 4)

Thus, the cost of the chair is $175. Now, to find the cost of the sofa we need to simply substitute C = 175 into our first equation, S = 3C - 50:

S = 3(175) - 50

S = 525 - 50

S = 475

Thus, the sofa costs $475.

3. Now that we know that the sofa costs $475 and the chair costs $175, all we need to do is to subtract the cost of the chair from the cost of the sofa to find the difference in price:

475 - 175 = 300

Therefor, the sofa costs $300 more than the chair (answer C).

viktelen [127]4 years ago
3 0
C . 300 is the answer
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The correct answer are

Sue interest : 169.6061952

Bill interest: 189.9131472


B. Bill will get more interest then sue


Explain


Sue principal balance p= 2300

Interest for 3 years so t= 3

Interest is compounded yearly n= 1

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A= 2300(1+2.4/100)^3 = 2300(1+0.024)^3 = 2300 x (1.024)^3 = 2469.6061952

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A= 1800(1+3.4/100)^3 = 1800 (1+0.034)^3 = 1800 (1.034)^3 = 1989.9131472

Interest in 3 yrs = 1989.9131472 - 1800 =

189.9131472



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