Answer:
252 ; 0.0059 ; 0.0074 ; 0.9926
Step-by-step explanation:
Day shift = 10
Swing shift = 8
Graveyard shift = 6
Total number of workers = 24
A.) Number of selections resulting in 5 workers coming from day shift :
10C5 = 10! ÷ (10-5)!5!
= (10*9*8*7*6) / (5*4*3*2*1)
= 252
B.) All 5 workers coming from day shift :
Required outcome = 10C5
Total possible outcomes = 24C5
10C5 ÷ 24C5
252 ÷ 42504
= 0.0059288
= 0.0059
C.) 5 selected workers are from the same shift :
[day shift + swing shift + graveyard shift] / total possible outcomes
[(10C5) + (8C5) + (6C5)] ÷ 24C5
(252 + 56 + 6) / 42504
= 0.0074
D.) What is the probability that at least two different shifts will be represented among the selected workers?
1 - [[(10C5) + (8C5) + (6C5)] ÷ 24C5]
1 - 0.0073875
= 0.9926124
= 0.9926
Answer:
x = 3
Step-by-step explanation:
Factor using difference of cubes and set each factor equal to 0.
The correct answer would be B because 88 divided by 11 would be 8 and therfore it would justift that the ration would be equal to 88:33
I multiplied the dimensions and divided it by 75, got 8.75 but you need to round in this situation, so 9
hope this helps :)
