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3 years ago

12

2z^8- 32z^8 Help plz

2 answers:

lora16 [44]3 years ago

4 0

Answer:

-30z^8

Step-by-step explanation:

2z^8- 32z^8

-30z^8

Ierofanga [76]3 years ago

3 0

Answer:

-30z^8

Step-by-step explanation:

$2 {z}^{8} - 32 {z }^{8} \\ = - 30 {z}^{8}$

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First calculate (-8x-15)=120

Then multiply - 11x120

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3 years ago

What is the solution to the equation below? ½ x+¾=⅔

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Answer:

$\boxed{x = - \frac{1}{6}}$

Step-by-step explanation:

$= > \frac{1}{2} x + \frac{3}{4} = \frac{2}{3} \\ \\ = > \frac{1}{2} x = \frac{2}{3} - \frac{3}{4} \\ \\ = > \frac{1}{2} x = ( \frac{2}{3} \times \frac{4}{4} ) - (\frac{3}{4} \times \frac{3}{3} ) \\ \\ = > \frac{1}{2} x = \frac{8}{12} - \frac{9}{12} \\ \\ = > \frac{1}{2} x = \frac{8 - 9}{12} \\ \\ = > \frac{1}{2} x = - \frac{1}{12} \\ \\ = > x = 2 \times ( - \frac{1}{12} ) \\ \\ = > x = - \frac{1}{6}$

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3 years ago

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Evgen [1.6K]

Answer:

Part 1) The scale factor is $1.5$

Part 2) The altitude QS is $4\ units$

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Part 4) The value of x is $12\ units$

Part 5) The perimeter of ABCDE is $46\ units$

Step-by-step explanation:

Part 1) Find the scale factor of triangle TQR to triangle NQP

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

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substitute the values

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we know that

To find the altitude QS, divide the altitude of triangle NQP by the scale factor

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Part 3) Find the scale factor of FGHJK to ABCDE

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

z-----> the scale factor

$z=\frac{AB}{FG}$

substitute the values

$z=\frac{10}{15}=\frac{2}{3}$

Part 4) Find the value of x

we know that

The value of x is equal to multiply the length side FK by the scale factor

so

$AE=FK(z)$

substitute the values

$AE=18(2/3)=12\ units$

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we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

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z-----> the scale factor

x-----> the perimeter of ABCDE

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we have

$z=\frac{2}{3}$

$y=15+9+12+15+18=69\ units$

substitute the values

$z=\frac{x}{y}$

$x=(z)(y)=\frac{2}{3}(69)=46\ units$

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