Answer: ARR = Average profit/Initial outlay x 100
ARR = $19,000/$250,000 x 100
ARR = 7.60%
The correct answer is C
Depreciation = Cost - Residual value/Estimated useful life
= $250,000 - $20,000/5 years
= $46,000 per annum
Average profit = Total profit/No of years
= $325,000/5
= $65,000
$
Average profit 65,000
Less: Depreciation 46,000
Average profit after depreciation 19,000
Explanation: In determining the accounting rate of return of the investment, there is need to calculate depreciation using straight line method. The amount of depreciation would be deducted from the average profit so as to obtain the average profit after depreciation. The average profit would be divided by the initial outlay in order to obtain the accounting rate of return.
Answer:
<em>The question option are:</em>
<em>1. For the current quarter what is the economy's income?
</em>
<em>2. For the current quarter, what is the economy's expenditure?
</em>
<em>3. In an economy, how are income and expenditure related?</em>
1. The economy's income for the current year is $450 because there is only one transaction that take place in the year worth of $450
2. The economy's expenditure of the current year is $450 because each transaction has two side. One is the Income, the other is Expenditure. The income is converted to expenditure.
3. In an economy, income and expenditure are related and they are equal. Each transaction has two side. One is the Income, the other is Expenditure. The income is converted to expenditure.
Answer:
To use brainly or to not use brainly. I dont like cheating but sometimes I realy need help.
Explanation:
Speak to their corporate consumer department.
Answer:
The incremental benefit cost ratio is less than 1 therefore we must select site 1.
Explanation:
The incremental BCR can be determined using the following formula
![\Delta BC_R = \frac{AW_B-AW_D-AW_M}{AW_i}](https://tex.z-dn.net/?f=%5CDelta%20BC_R%20%3D%20%5Cfrac%7BAW_B-AW_D-AW_M%7D%7BAW_i%7D)
8% , 10)
⇒ ![AW_C= 1,000,000 \times \frac{0.08}{1-1.08^-^1^0}](https://tex.z-dn.net/?f=AW_C%3D%201%2C000%2C000%20%5Ctimes%20%5Cfrac%7B0.08%7D%7B1-1.08%5E-%5E1%5E0%7D)
⇒
8%, 20)
⇒ ![AW_2= 2,000,000 \times \frac{0.08}{1-1.08^-^2^0}](https://tex.z-dn.net/?f=AW_2%3D%202%2C000%2C000%20%5Ctimes%20%5Cfrac%7B0.08%7D%7B1-1.08%5E-%5E2%5E0%7D)
⇒
= $203,704.42
Incremental initial investment = 203,704.42 - 149,029.49
= $ 54,674.93
Incremental benefits = 580,000 - 520,000 = 60,000
Incremental O&M = 75,000 - 80,000 = - $ 5000
Incremental Disbenefits = 140,000 - 90,000 =$ 50,000
![\Delta BC_R = \frac{60,000-50,000-(-5000)}{54,674.93} \\\\\Delta BC_R=0.2743](https://tex.z-dn.net/?f=%5CDelta%20BC_R%20%3D%20%5Cfrac%7B60%2C000-50%2C000-%28-5000%29%7D%7B54%2C674.93%7D%20%5C%5C%5C%5C%5CDelta%20BC_R%3D0.2743)
All solving using the present worth method also incremental benefit cost ratio comes out to be 0.2743.
The incremental benefit cost ratio is less than 1 therefore we must select site 1.