What is the value of k in y = kx, if y = 12 when x = 24?
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X gallons of a 60% acid solution contains 60%×x=0.6x gallons of acid.
50 gallons of a 24% acid solution contains 24%×50=0.24×50=12 gallons of acid.
After mixing, there will be x+50 gallons of a solution, and 0.6x+12 gallons of acid. The concentration must be 50%, so the volume of acid divided by the volume of the solution is 50%, or 0.5.
The answer is A. 130 gallons.
50 gallons of a 24% acid solution contains 24%×50=0.24×50=12 gallons of acid.
After mixing, there will be x+50 gallons of a solution, and 0.6x+12 gallons of acid. The concentration must be 50%, so the volume of acid divided by the volume of the solution is 50%, or 0.5.
The answer is A. 130 gallons.