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WARRIOR [948]
2 years ago
15

Unit 7: Polygons & Quadrilaterals Homework 4: Rhombi and Squares

Mathematics
1 answer:
PolarNik [594]2 years ago
3 0

Answer:

CD=28

FD=16

EF=22.978

EC=45.956

Step-by-step explanation:

hope it helps...

have a great day!!

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Hello I don’t understand question 9 a and b. Please show working out.<br> Thanks
brilliants [131]
A) I would make the positive integer x and then form an equation.

x + 30 = x^2 - 12
x + 42 = x^2
0 = x^2 - x - 42 this can be factorised
(x - 7) ( x + 6) Therefore x = 7 or x = -6

Since the question asks for a positive integer the answer is 7.

B) two positive numbers x and y.

X - y = 3
x^2 + y^2 = 117

Use these simultaneous equations to figure out each number.

Rearrange the first equation

x = y + 3

Then substitute it into the second equation.

(y+3)^2 + y^2 = 117
y^2 + 6y + 9 + y^2 = 117
2y^2 + 6y - 108 = 0
then factorise this.
(2y - 12) (y + 9)

This means that y = 6 or y = -9 but it’s 6 because that’s the only positive number.

Use y to find x

x = y + 3
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3 0
2 years ago
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