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Helen [10]
3 years ago
12

How to understand amortized analysis potential?

Computers and Technology
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
Since you gave kind of a vague question. I'll just go with the basics. Amortized analysis in computer science is basically the study of worst case run times regarding a sequence of operations.

When looking at potential, it is the physicist's method.
phi (initial state) =0 and every state after is larger than 0.
It keeps track of time but relies on states to know where it is.

The equation C +phi (state')-phi(state) is the main equation. C is the time for an operation, "state" is before and "state'" is after.

There are sets of equations that dictate average run time with this.

ex.
phi (H)= 2n-m. n=number of elements, m=size of array.
This equation is used to calculate the time to double the size.
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It is helps in achieving the accuracy as compared with manual testing and also also function without any human interruption.It produces the test scripts that can be re-used.

8 0
3 years ago
Which method tries all possible passwords until a match is found?
barxatty [35]
Brute force is this approach to password cracking. It tires all possible password combinations until a correct match between the hashes is found. It may make use of rainbow tables which contain precomputed password-hash combinations.

Please remember that it helps to provide the choices that match your question. This can help you get an accurate answer and have your question answered much quicker.
7 0
3 years ago
Write a routine to interchange the mth and nth elements of a singly-linked list. You may assume that the ranks m and n are passe
IRINA_888 [86]

Answer:

//The routine to swap m th and nth ranked elements

void swapmAndn(int m, int n)

{

  //Set the linked list head node

  Linked_Node **node_head

  //To find the m ranked node

  //set previous node  

  Linked_Node *node_prev = NULL;

 

  //set node to store m ranked node as head node

  Linked_Node *node_current_m = *node_head;

 

  //set the rank as rm=1

  rm =1

  //traverse to find the m ranked node

  while (node_current_m && rm<m)

  {    

      node_prev = node_current_m;

      node_current_m = node_current_m->next;

      rm++;

  }

 

  //To find the n ranked node

  //set previous node  

  Linked_Node *node_prev_n = NULL;

 

  //set node to store n ranked node as head node

  Linked_Node *node_current_n = *node_head;

 

  //set the rank as rn=1

  rn =1

  //traverse to find the n ranked node

  while (node_current_n && rn<n)

  {    

      node_prev_n= node_current_n;

      node_current_n = node_current_n->next;

      rn++;

  }

 

  //if m is not first ranked node

  if (node_prev != NULL)

      //set node_current_n as previous node

      node_prev->next = node_current_n;

 

  //otherwise Set the node_current_n

  else

      *node_head = node_current_n;

 

  // If n is not first ranked node

  if (node_prev_n!= NULL)

      node_prev_n->next = node_current_m;

  else

      *node_head = node_current_m;

 

  //now swap the next pointers also

  //to make the swap process complete  

  Linked_Node *temp = node_current_n->next;

  node_current_n->next = node_current_m->next;

  node_current_m->next = temp;

}

Explanation:

3 0
3 years ago
How do you put a picture when you ask a question?
Setler [38]

Answer:

there should be an option to attach an item. if not try pasting it

Explanation:

5 0
3 years ago
Read 2 more answers
C programming:
mixas84 [53]
IsTeenager = ( ( kidAge >= 13 ) && ( kidAge <= 19 ) ) ? true : false;

Another way:

if( ( kidAge >= 13 ) && ( kidAge <= 19 ) )
  isTeenager = true;
else
   isTeenager = false;
8 0
3 years ago
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