Question

(09.01 MC)

Answer 1

Answer:

Function 1 has the least minimum value and its coordinates are (2. - 7).

Step-by-step explanation:

The first function is

$f(x)=2x^{2} -8x+1$

The second function is

x   g(x)

-2    2

-1    -3

0     2

1     17

The vertex has coordinates of $V(h,k)$, where $h=-\frac{b}{2a}$ and $k=f(h)$.

Let's find the vertex for the first function where $a=2$ and $b=-8$.

$h=-\frac{-8}{2(2)}=2$

$k=f(2)=2(2)^{2} -8(2)+1=8-16+1=-8+1=-7$

Therefore, the vertex of the first function is at $(2,-7)$.

Now, the minimum value of the second function can be deducted from its table, which is $(-1,-3)$.

Therefore, $f(x)$ has -7 as minimum value and $g(x)$ has -3 as minimum vale.

So, the right answer is B, because -7 is less than -3.