All categories

4 years ago

A rectangular prism has a length of 12in, a height of 5in, and a width of 8in. What is it’s volume, in cubic in?

Mathematics

1 answer:

marissa [1.9K]4 years ago

4 0

Answer:

12 times 2 is 24. 5 times 2 is 10. 8 times 2 is 16. 24 plus 10 plus 16 is 50

Step-by-step explanation:

You might be interested in

What is the probability that all three coins will land on the same side

scZoUnD [109]

1/2 * 1/2 * 1/2 = 1/8 <==

7 0

4 years ago

Simplify square root of five times the quantity six minus four square root of three.

NemiM [27]

6√5 - 4√3-

i took the test but sorry if its wrong

5 0

3 years ago

the bowling alley charges a flat rate of $50 for a birthday party plus $4.25 per person. If Emanuel only has $125 to spend. How

Maksim231197 [3]

125 > 50 + 4.25*p

subtract 50 from each side

75 =>4.25p

divide by 4.25

p>17.64

He may invite up to 17 people ( if he doesn't have to pay for himself)

He may invite 16 if he has to pay for himself

3 0

3 years ago

Explain why the commutative property does not work for subtraction or division

nirvana33 [79]

Answer:The reason there is no commutative property for subtraction or division is because order matters when performing these operations.

Step-by-step explanation:

3 0

3 years ago

The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

4 years ago