What is 12 over 42 in simplest form?
2 answers:
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Answer:
Step-by-step explanation:
From the given data, it can be observed that there are two number that are abnormal and extremely different from others, 322 and 19. Eliminating these two numbers would reduce the error that can be generated.
Then to obtain the best single result from the measurements, find the mean of the other numbers.
i.e 52.3, 52.5, 52.2, 52.6
Mean =
=
= 52.4
Thus the best single result that can be obtained is 52.4.
<h3>Answer: choice E</h3><h3>total area = pi*r^2 + (10 - (1/2)pi*r)^2</h3>
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How I got that answer:
Draw out a line segment and label it to be 40 meters long. Somewhere in the middle (not the exact midpoint necessarily), draw a cutting line to divide the segment into two (not necessarily equal) parts. The first part is x units long. The remaining bit is 40-x units long. See the attached image below. The drawing is optional, but it might help to visually see how the two parts interact.
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The wire that is x units long is used to form a circle of radius r. The question is: what is x in terms of r?
The circumference of the circle of radius r is
C = 2*pi*r
If we cut the circle and unroll it out into a straight line, then its perimeter or circumference will stretch into a line of length 2*pi*r. So this must be the length of x.
x = 2*pi*r
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The value of 40-x is then
40-x = 40-2pi*r
which will be used to form the square.
The total perimeter of the square is P = 4*s, where s is the side length. Solving for s gets to
s = P/4
Plug in P = (40-2pi*r) and simplify
s = P/4
s = (40-2pi*r)/4
s = 40/4-(2pi*r)/4
s = 40/4-(2/4)pi*r
s = 10 - (1/2)pi*r
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We know the side length of the square, which can be used to find the area of the square
A = area of square
A = s^2
A = (10-(1/2)*pi*r)^2
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M = area of circle = pi*r^2
N = area of square = (10-(1/2)*pi*r)^2
total area = M+N
total area = pi*r^2 + (10-(1/2)*pi*r)^2