The total mass, in kilograms, of the nails the carpenter bought is 3.9 kilogram
<h3><u>Solution:</u></h3>
Given that carpenter bought 750 nails
Each nail has a mass of 
kilogram
To find: total mass, in kilograms of the nails bought
The total mass of the nails bought can be found out by multiplying number of nails bought by mass of each nail
Number of nails bought = 750
Mass of each nail = kilogram
total mass of the nails bought = number of nails bought x mass of each nail
Thus the total mass of nails bought is 3.9 kilogram
Answer:
B
Step-by-step explanation:
Since ∠ E = ∠ F then the triangle is isosceles and DF = DE, that is
6x = x + 2y ( subtract x from both sides )
5x = 2y ( subtract 2y from both sides )
5x - 2y = 0 → (1)
and perimeter = 29, that is
6x x + 2y + 5x - y = 29 , simplifying
12x + y = 29 → (2)
Multiply (2) by 2
24x + 2y = 58 → (3)
Add (1) and (3) term by term to eliminate y, that is
29x = 58 ( divide both sides by 29 )
x = 2
Substitute x = 2 into (2) and evaluate for y
12(2) + y = 29
24 + y = 29 ( subtract 24 from both sides )
y = 5
Thus
FE = 5x - y = 5(2) - 5 = 10 - 5 = 5 → B
The answer would be -1 +x
The diagram of the right-angled triangle is shown below
Using the Pythagoras theorem
6² = a²+a²
36 = 2a²
18 = a²
a = √18 = 3√2
180/3 = 60 and I believe x is 60/2 = 30
