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Nostrana [21]
4 years ago
13

A, B and C form the vertices of a triangle. BC = 6.9cm and ∠ CBA = 137°. Given that the area of the triangle is 12.6cm^2, calcul

ate the perimeter of the triangle rounded to 1 DP.
Mathematics
1 answer:
Anon25 [30]4 years ago
8 0

Answer:

9304t5492860534795782437904209872423897897458790532870925879048790248309787904879525492898977042247980424372

Step-by-step explanation:

assho;le

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GUYS PLEASE HELP!!!!
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The first two equations are correct
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3 years ago
What is the inverse of the function f(x) = 2x + 1?
Luda [366]

Answer:

f^{-1}(x)=\frac{1}{2}x-\frac{1}{2} ⇒ answer 1

Step-by-step explanation:

* Lets explain how to find the inverse of a function

- To find the inverse of a function :

# Write y = f(x)

# Switch the x and y

# Solve to find the new y

# The new y is f^{-1}

* Lets solve the problem

∵ f(x) = 2x + 1

- Put y = f(x)

∴ y = 2x + 1

- Switch x and y

∴ x = 2y + 1

- Solve to find the new y

∵ x = 2y + 1

- Subtract 1 from both sides

∴ x - 1 = 2y

- Divide both sides by 2

∴ (x - 1)/2 = y

- Divide each term in the left hand side by 2

∴ y = 1/2 x - 1/2

- Replace y by f^{-1}

∴ f^{-1}(x)=\frac{1}{2}x-\frac{1}{2}

* The inverse of the function is f^{-1}(x)=\frac{1}{2}x-\frac{1}{2}

7 0
4 years ago
Read 2 more answers
Question from ucscout need help asap
Kobotan [32]

Answer:

A.S.A congurency.

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3 years ago
Anyone knows the answer
murzikaleks [220]

Answer:C

Step-by-step explanation:

3.1 x 10^(-4) x 8.5 x 10^(-2)

3.1 x 8.5 x 10^(-4) x 10^(-2)

26.35 x 10^(-4-2)

26.35 x 10^(-6)

2.635 x 10^1 x 10^(-6)

2.635 x 10^(1-6)

2.635 x 10^(-5)

3 0
4 years ago
How to find the area of a regular hexagon with a radius of 12 inches? Please help
Volgvan
\begin{gathered} In\text{ this case, as a regular hexagon} \\ \text{radius = side} \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}side^2}{2} \\ \text{side}=12in \\ side^2=144in^2 \\ Area\text{ =}3\cdot\frac{\sqrt[]{3}\cdot(144in^2)}{2} \\  \\ \text{Area}=374.1in^2 \\ \text{The regular hexagon's area is }374.1in^2 \end{gathered}

8 0
1 year ago
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