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natulia [17]
3 years ago
8

What is the solution to the system of equations below? 2 x + 3 y = 17. 3 x + 6 y = 30. (Negative 7, 24) (3, 4) (4, 3) (24, Negat

ive 7)

Mathematics
1 answer:
butalik [34]3 years ago
6 0

Answer:

work is shown and pictured

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What is tje equation for the linear function whose graph contains the points (2,5) and (3,0) ?
dolphi86 [110]
In order to find a slope, there is an equation:

Y2-Y1/X2-X1

X1=2
X2=3
Y1=5
Y2=0

0-5= -5
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Since slope is written as Y/X, slope would be-5/1 or simply, -5.

Now, we need to find the y-intercept.

To do this, shift the original equation:

Original equation: y=-5x+b

Shifted equation: b=y+5x

Now, plug in one of the points.

Let's use (2,5)

b=5+5(2)

5*2=10
10+5=15

y-intercept=15

So, the full equation of the line would be:

y=-5x+15
4 0
3 years ago
Haven't unpaid credit card balance is $2103.23 his APR is 14.4% what is his new balance if you made one new transaction for $390
Effectus [21]
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3 0
3 years ago
Select the correct answer.
Valentin [98]

Answer:

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7 0
3 years ago
Read 2 more answers
Third-degree, with zeros of -4, -2, and 1, and a y-intercept of -11.
Cloud [144]

\begin{cases} x = -4\implies &x+4=0\\ x=-2\implies &x+2=0\\ x=1\implies &x-1=0 \end{cases}\qquad \implies (x+4)(x+2)(x-1)=\stackrel{y}{0}

now, that's the equation or polynomial in factored form, hmmm we also know that it has a y-intercept of -11, namely, when x = 0  y = -11, well let's plug in a factor to it, that will reflect those values, namely say hmmm factor "a", so

(x+4)(x+2)(x-1)=y\qquad \stackrel{\textit{adding "a" factor for vertical shift}}{a(x+4)(x+2)(x-1)}=y \\\\\\ \stackrel{\textit{we know that when x = 0, y = -11}}{a(0+4)(0+2)(0-1)=-11}\implies -8a=-11\implies a=\cfrac{-11}{-8}\implies a = \cfrac{11}{8} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\mathbb{FOIL}}{\cfrac{11}{8}(x^2+6x+8)}(x-1)=y\implies \cfrac{11}{8}(x^3+6x^2+8x-x^2-6x-8)=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{11}{8}(x^3+5x^2+2x-8)=y~\hfill

4 0
2 years ago
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