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3 years ago

10

I need help on number 9, picture is included!

1 answer:

saveliy_v [14]3 years ago

3 0

Ok unit conversions

you know that 12 inches are in a foot
and 100 centimeters are in 1 meter

so starting with a)
you start with 2 ft^2

$2 ft^2 = \frac{2 ft^2}{} \times \frac{12 in}{1 ft} = 24 ft\ in = \frac{2 ft \ in }{} \times \frac{12 in}{1 ft} = 288 in^2$

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How do you convert units within a measurement system?

Anit [1.1K]

To convert among units in the metric system, identify the unit that you have, the unit that you want to convert to, and then count the number of units between them. If you are going from a larger unit to a smaller unit, you multiply by 10 successively.

5 0

3 years ago

1. The teacher assigns homework after 7/10

asambeis [7]

Answer:

B) Likely

Step-by-step explanation:

Unlikely = < 50%

Likely = > 50%

Certain = 100%

Equally likely = 50%

8 0

3 years ago

Paul traded 13 baseball card to Dan for 4 new packs of 6 cards each. Paul lost 3 cards. He now has 75 cards. How many cards did

melomori [17]

Answer:

The number of cards Paul had at the beginning was 64 cards

Step-by-step explanation:

Here we have a word problem as follows

Paul traded 13 baseball card to Dan for 4 new packs of 6 card each

Number of cards received from Dan = 6 × 4 = 24

Number of cards traded to Dan = 13

Net number of cards traded = 24 - 13 = 11

Total number of cards Paul now has = 75 cards

Therefore since Paul gained 11 cards to make his total number of cards = 75, then;

The initial amount of cards Paul had = 75 - 11 = 64 cards.

3 0

3 years ago

An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

andrey2020 [161]

Answer:

The probability that A selects the first red ball is 0.5833.

Step-by-step explanation:

Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.

To find : What is the probability that A selects the first red ball?

Solution :

A wins if the first red ball is drawn 1st,3rd,5th or 7th.

A red ball drawn first, there are $E(1)= ^9C_2$ places in which the other 2 red balls can be placed.

A red ball drawn third, there are $E(3)= ^7C_2$ places in which the other 2 red balls can be placed.

A red ball drawn fifth, there are $E(5)= ^5C_2$ places in which the other 2 red balls can be placed.

A red ball drawn seventh, there are $E(7)= ^3C_2$ places in which the other 2 red balls can be placed.

The total number of total event is $S= ^{10}C_3$

The probability that A selects the first red ball is

$P(A \text{wins})=\frac{(^9C_2)+(^7C_2)+(^5C_2)+(^3C_2)}{^{10}C_3}$

$P(A \text{wins})=\frac{36+21+10+3}{120}$

$P(A \text{wins})=\frac{70}{120}$

$P(A \text{wins})=0.5833$

6 0

3 years ago

Consider the function below.

vovangra [49]

An inverse function reverses (x, f(x)) to make it (f(x), x).

The 1st selection does that.

5 0

3 years ago

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