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Natalija [7]
3 years ago
14

Is square root of 140 a rational or irrational number ?

Mathematics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer: The square root of 140 is irrational.

Step-by-step explanation:

Take the square root of 140:

11.8321595662

This is an imperfect square root, and all imperfect square roots are irrational.

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What number needs to be added to 5 and 3 so that the ratio of the first number to the second
Mashcka [7]

Answer:

3

Step-by-step explanation:

Choose a variable to represent the number to be added to 5 and 3.

\frac{5+x}{3+x}=\frac{4}{3}

"Cross-multiply."

3(5+x)=4(3+x)\\\\15+3x=12+4x\\\\15=12+x\\\\3=x

Check:  The ratio of 5+3 to 3 + 3 is 8:6, equal to the ratio 4:3.

5 0
3 years ago
A plane, parallel to the base of a cone intersects the cone at the midpoint between points A and B. Determine the area of the cr
Fed [463]

Given that point of intersection is at half of the height, by similarity of triangles, the radius is half of 

The the area is Pi*r^2 = Pi*(3in)^2 = Pi*9 in^2 = 9Piin^2


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4 years ago
a certain smartphone family plan costs 55$ per month plus additional usage costs. if x is the number of cellphone minutes used a
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7 0
3 years ago
Given the functions, f(x) = 3x - 6 and g(x) = x2 + 5x + 7, perform the indicated operation. When applicable, state the domain re
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Step-by-step explanation:

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8 0
3 years ago
What is the sum of the series? 4 ∑k=1 (2k^2−4)
larisa86 [58]

The sum of the series \sum_{k=1}^{4}\left(2 k^{2}-4\right) is 44.

Step-by-step explanation:

The given series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

To find the sum of the series, we need to substitute the values for k in the series.

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]

Now, simplifying the square terms, we get,

[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]

Multiplying the terms,

[2-4]+[8-4]+[18-4]+[32-4]

Subtracting the values within the bracket term, we get,

-2+4+14+28

Now, adding all the terms, we get the sum of the series,

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

Thus, the sum of the series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

8 0
3 years ago
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