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3 years ago

Is square root of 140 a rational or irrational number ?

Mathematics

1 answer:

Stolb23 [73]3 years ago

5 0

Answer: The square root of 140 is irrational.

Step-by-step explanation:

Take the square root of 140:

11.8321595662

This is an imperfect square root, and all imperfect square roots are irrational.

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Find the product. 7xy(3x2y3) PLEASES HELP!!! ASAP!!!

Marizza181 [45]

Answer:

21x³y^4

Step-by-step explanation:

7xy(3x^2y^3)=

21x³y^4

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4 years ago

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My textbook doesn't explain square roots well. Can someone help me understand? Example 1 is the square root of 9

Vilka [71]

A square root is doing the opposite of squaring. Squaring is multiplying a number by itself. Square rooting is trying to figure out what number squares into the number you have currently.
For your Example 1, the square root of 9 is 3.
3 x 3 = 9.
Some better examples are:
4 x 4 = 16.
4 is the square root of 16, and 16 is the square of 4.

7 0

3 years ago

Order of operations my question is 4×4+3

ipn [44]

Answer:

1. multiply 4x4 (which equals 16)

2. add that answer to 3 (which equals 19)

Step-by-step explanation:

Use PEMDAS (Solve in parentheses first, then exponents, multiplication, division, addition, and subtraction in that order) for the correct order of operations

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3 years ago

Read 2 more answers

Evaluate: -4(-1/8 + 0.3) A. - 1.7 B. - 0.7 C. 0.8 D. 2

kobusy [5.1K]

$-4(- \dfrac{1}{8} + 0.3)$

Rewrite decimal to fraction:
$= -4(- \dfrac{1}{8} + \dfrac{3}{10})$

Change the denominators to be the same:
$= -4(- \dfrac{1 \times 5}{8 \times 5} + \dfrac{3 \times 4}{10 \times 4})$

Simplify each fraction:
$= -4(- \dfrac{5}{40} + \dfrac{12}{40})$

Add the fraction in the bracket:
$= -4( \dfrac{7}{40})$

Multiply:
$= -\dfrac{7}{10}$

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4 years ago

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Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.7

Zinaida [17]

Answer:

(a) The probability that the sample average sediment density is at most 3.00 is 0.092.

The probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b) The sample size must be at least 77.

Step-by-step explanation:

The random variable X ca be defined as the sediment density (g/cm) of a specimen from a certain region.

The random variable X is normally distributed with mean, μ = 2.7 and standard deviation, σ = 0.75.

(a)

A random sample of n = 25 specimens is selected.

Compute the probability that the sample average sediment density is at most 3.00 as follows:

Apply continuity correction:

$P(\bar X\leq 3.00)=P(\bar X$

$=P(\bar X$

$=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}$

$=P(Z$

Thus, the probability that the sample average sediment density is at most 3.00 is 0.092.

Compute the probability that the sample average sediment density is between 2.70 and 3.00 as follows:

$P(2.70$

$=P(0$

*Use a z-table.

Thus, the probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b)

It is provided that:

$P(\bar X\leq 3.00)\geq 0.99$

$P(\bar X$

$P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}$

$P(Z$

The value of z for the probability above is

z ≥ 2.33

Compute the value of n as follows:

$\frac{|2.50-2.70|}{0.75/\sqrt{n}}\geq 2.33$

$\frac{|-0.20|}{2.33}\geq \frac{0.75}{\sqrt{n}}$

$\sqrt{n}\geq \frac{0.75\times 2.33}{|-0.20|}\\\sqrt{n}\geq 8.7375\\n\geq 76.3439\\\approx n\geq 77$

Thus, the sample size must be at least 77.

8 0

3 years ago