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3 years ago

5t+5/4-1=4t-3/5maths class 8

Mathematics

1 answer:

Aleks [24]3 years ago

6 0

Answer:

3.4

Step-by-step explanation:

5t+5/4-1=4t-3/5. cross multiply over the bracket

(5t+5)5=(4t-3)(4-1)

25t + 25 = -16t -4- 12 - 3

Combine the like terms

25t - 16t +4t = -4-12-3-25

13t = - 44

Divide both sides by 13

3.38

3.4 approximately

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What is the answer to 1+3x=37?

goldenfox [79]

Answer:

x=12

Step-by-step explanation:

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Vitek1552 [10]

Answer: 0.992

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3 years ago

Integrate xe^(-x^2).

Gekata [30.6K]

You can easily integrate it using a simple substitution:

$\large\begin{array}{l} \mathsf{\displaystyle\int\!x\,e^{-x^2}\,dx}\\\\ =\mathsf{\displaystyle\int\!\left(-\frac{1}{2}\right)\cdot (-2)x\,e^{-x^2}\,dx}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\int\!\,e^{-x^2}\cdot (-2x)\,dx\qquad\quad(i)}\\\\ \end{array}$

$\large\begin{array}{l} \textsf{Let}\\\\ \mathsf{-x^2=u,}\quad\textsf{then}\quad\mathsf{-2x\,dx=du}\\\\\\ \textsf{so (i) becomes}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\int\!e^u\,du}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\cdot e^u+C}\\\\ =\mathsf{\displaystyle-\,\frac{1}{2}\cdot e^{-2x}+C}\\\\\\ \boxed{\begin{array}{c} \mathsf{\displaystyle\int\!x\,e^{-x^2}\,dx=-\,\frac{1}{2}\,e^{-x^2}+C} \end{array}}\qquad\checkmark \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2159730

$\large\textsf{I hope it helps. :-)}$

Tags: <em>integrate substitution indefinite integral exponential composite calculus</em>

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4 years ago

5t+5/4-1=4t-3/5maths class 8​

5t+5/4-1=4t-3/5maths class 8