a^2 + b^2 = c^2
Let c = hypotenuse = 2x
One of the legs = x. Let a or b = x.
I will let a = x. We can then say that b = 3.
3^2 + x^2 = (2x)^2
9 + x^2 = 4x^2
9 = 4x^2 - x^2
9 = 2x^2
9/2 = x^2
sqrt{9/2} = sqrt{x^2}
3/sqrt{2} = x
Rational denominator.
[3•sqrt{2}]/2 = x = a
Side 3 is given to be 3 feet. So, b = 3.
Hypotenuse = 2x
Hypotenuse = 2([3•sqrt{2}]/2)
Hypotenuse = 3•sqrt{2}
Understand?
The three sides are 3, [3•sqrt{2}]/2 and
3•sqrt{2}.
10x8? 80. 10, 20, 30, 40, 50, 60, 70, 80
Answer:
312
Step-by-step explanation:
3/4 × 32 = 24
9 × 32 = 288
288 +24=312
Answer:
The answer to your question is: x > - 32 / 9
Step-by-step explanation:
2[ -5/2 (3x + 4) < 6 - 3x ] x (2)
-5 (3x + 4) < 12 - 6x
-15x - 20 < 12 - 6x
-15x + 6x < 12 + 30 Simplify
- 9 x < 32 solve for x
x > - 32 / 9 result
Answer:
Hence two consecutive even integers are 14 and 16
Step-by-step explanation:
Let x and x+2 be the two consecutive even integers
Then according to the given statement in the question
8x = 7(x+2)
<u>Distributive property </u>
8x=7x+14
<u>Subtraction Property of Equality</u>
8x-7x = 14+7x-7x
<u>Simplifying</u>
x = 14
So the first integer is 14 and second is:
x+2 = 14+2 = 16
Hence two consecutive even integers are 14 and 16 ..
