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3 years ago

In a right triangle the side c opposite the right angle is called the hypotenuse, and the other two sides a and b are

Mathematics

2 answers:

RSB [31]3 years ago

4 0

Answer:

The hypotenuse of the triangle measures 13 inches.

Step-by-step explanation:

Since the Pythagorean theorem states that in any right triangle the lengths of the three sides are related by the equation A ^ 2 + B ^ 2 = C ^ 2, to determine the length of the hypotenuse in a right thangle with legs 5 inches and 12 inches the following calculation should be performed:

5 ^ 2 + 12 ^ 2 = X ^ 2

25 + 144 = X ^ 2

√169 = X

13 = X

Therefore, the hypotenuse of the triangle measures 13 inches.

Drupady [299]3 years ago

3 0

Answer:

Step-by-step explanation:

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$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

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$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

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