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AURORKA [14]
3 years ago
15

In a right triangle the side c opposite the right angle is called the hypotenuse, and the other two sides a and b are

Mathematics
2 answers:
RSB [31]3 years ago
4 0

Answer:

The hypotenuse of the triangle measures 13 inches.

Step-by-step explanation:

Since the Pythagorean theorem states that in any right triangle the lengths of the three sides are related by the equation A ^ 2 + B ^ 2 = C ^ 2, to determine the length of the hypotenuse in a right thangle with legs 5 inches and 12 inches the following calculation should be performed:

5 ^ 2 + 12 ^ 2 = X ^ 2

25 + 144 = X ^ 2

√169 = X

13 = X

Therefore, the hypotenuse of the triangle measures 13 inches.

Drupady [299]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Edge 2021

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Please help, this is due tonight
dolphi86 [110]

Answer:

It's B

Step-by-step explanation:

Just divide y by x. For example: 6.6 / 6 = 1.1. This would be B! Hope this helps!

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3 years ago
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SOMEONE ANSWER AND EXPLAIN PLEASE ILL MARK BRAINLIEST
VikaD [51]

Answer:

(2,1)

Step-by-step explanation:

This is the answer by substitution.

change 2x+y=5 to y=5-2x

5x-2(5-2x)=8

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y=5-2(2)

y = 1

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You're welcome!!!

6 0
2 years ago
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
Find the greatest common factor.<br> 6z^3 , 8z
harina [27]

Answer:

The answer is below.

Step-by-step explanation:

The GCF is 2z because it is the biggest number that can be factored out of both numbers. Also, since the 8z has no exponent, the GCF of 2z doesn't need one either.

If this answer is correct, please make me Brainliest!

4 0
3 years ago
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