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Setler [38]
4 years ago
11

PLEASE HELP Choose the equation that represents the graph below.

Mathematics
2 answers:
swat324 years ago
7 0

Answer:

i'd like to say that the correct answer is the one at the very bottom; y=x+3

Alexus [3.1K]4 years ago
3 0

Answer:

y = x + 3

Step-by-step explanation:

All the options have the slope intercept form:

y = mx + b

From the picture, we can see that the y-intercept is 3, that is, y = 3 when x = 0. So, b = 3

From the picture, points (-3, 0) and (0, 3) are on the line. Then, the slope is:

m = (3 - 0)/(0 - (-3)) = 1

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There are many cylinders with radius 6 meters. Let h represent the height in meters and V represent the volume in cubic meters.
KiRa [710]

The equation that represents the volume of the cylinder is 36πhhh m³.

Explanation:

Formula: volume of a cylinder = πr²h

pi =  π = 22/7

r = radius

6² πhhh

36πhhh m³

4 0
3 years ago
A section of ground measures 1.5 cubic meters and contains 0.78 gram of gold. What is the amount of gold per cubic meter? Enter
Marta_Voda [28]
To find the gold per cubic meter you have to divide the amount of gold by the size of the area. So you would do .78/1.5 which would give you .52g/m3
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3 years ago
Which expression is equivalent to 9x − 12?
beks73 [17]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Find the greatest common factor of 9 and 12

It would be 3

9x/3 = 3x

-12/3 = -4

The correct option is C. 3(3x - 4)

<h3><u>✽</u></h3>

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3 0
3 years ago
Read 2 more answers
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
4 years ago
X^2 +<br>1/x^2<br>+12(x+1/x) +38, <br>​
sergiy2304 [10]

Answer:

44

Step-by-step explanation:

5 0
3 years ago
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