First, you'll use the "Log power rule," which says that

. In this case, you're going from the form on the right (with p in front of the log) to the form on the left (with p in the exponent position). So, the expression becomes:

Then, you'll use the "Log product rule," which says that

. Again, you're going from the form on the right to the form on the left (basically, from the sum of the logs, to a log of the products). So you get:

There's your expression simplified into a simple logarithm.
Answer:
1x2x4x7x87
Step-by-step explanation:
In matching an equation with a graph, there are many ways, one of them i using the Slope Intercept Form of the graph, convert the graph and then compare the slope of the two. I hope you are satisfied with my answer and feel free to ask for ore if you have question and further clarification.
Answer:
The circle one
Step-by-step explanation:
What you need to do is count the number of squares or slices it has and then count how Buchanan the chunk is divided into, should be 6
Step-by-step explanation:
all the equations x could be perpendicular to the equation y.
so, the anawer :
B. x = 8
D. x = -2