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Amiraneli [1.4K]
3 years ago
9

I need help with this please ​

Mathematics
1 answer:
stepladder [879]3 years ago
4 0

Answer:

supplementary

Step-by-step explanation:

Since a and b form a straight line, they will add to 180 degrees

Two angles that add to 180 degrees are supplementary angles

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What is the slope-intercept equation of this line?
svet-max [94.6K]
Your answer would be A. y = -3 + 4

the line intercepts the y axis at +4
and the line decreases 3 units down and one unit to the right which makes the slope ( rise over run) -3/1 but you would just say -3
8 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
I think of a number multiply by two then subtract 9
EastWind [94]

Answer:

2n - 9

Step-by-step explanation:

Let the number be n.  Then "a number multiply by two then subtract 9" yields

2n - 9

3 0
3 years ago
Is the term (x+1) a factor of the polynomial shown below? <br> f(x)=x^3-10x^2+27x-12
Ksenya-84 [330]

We can tell if this is a factor of the polynomial shown by using the remainder theorem.

First, we need to set x + 1 equal to 0.

x + 1 = 0

Now, we solve for x.

x = -1

Now, we can plug this value into the polynomial, and if the solution is 0, it means there is a remainder of 0, which means they divide perfectly.

(-1)^3 - 10(-1)^2 + 27(-1) - 12 = -50

x + 1 is not a factor of the provided polynomial.

7 0
3 years ago
Read 2 more answers
To join a health club, a person must pay a $75 one-time fee plus a charge of $30 per month. This situation can be presented by a
Rudiy27

Answer:

y = 30x + 75

Step-by-step explanation:

every month you're paying 30 dollars for a fee.

the 75 dollars is simply the "down payment" so to say.

m is the constant growth or the continuous growth or the charge per month.

5 0
3 years ago
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