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Sophie [7]
3 years ago
9

Type the missing numbers in this sequence:9, 3,-3,__, -15,__,-27

Mathematics
1 answer:
padilas [110]3 years ago
6 0
The formula for this equation is -6 for each number. So the answer your looking for is 9...3....-3....-9....-15.....-27. Hope I helped you out.
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A video game club charges a fixed annual membership fee of $20 and $2 per video game rented. Let f(n) represent the total annual
djverab [1.8K]
The total cost for video rental, f(n), is the sum of the membership fee and the cost of renting video game. The latter is the product of cost per video game times n video games. The correct equation used to represent the total cost is,
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Since the membership is increased by 15, the new equation is,
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4 0
2 years ago
Read 2 more answers
Y=-2х - 4 y=x - 5 how many solutions does this have​
spayn [35]

Answer:

one solution

Step-by-step explanation:

-2x - 4 = x - 5

-3x - 4 = -5

-3x = -1

x = 1/3

y = 1/3 - 5

y = 1/3 - 15/3

y = -14/3

(1/3, -14/3)

5 0
3 years ago
Which function has x-intercepts of 3 and 8 and contains the point (–1, –2)?
mojhsa [17]
This is how you do it.

y = a(x - 3)(x - 8) 
<span>-2 = a(-1 - 3)(-1 - 8) </span>
<span>-2 = 36a </span>
<span>- 1 / 18 = a </span>
<span>y = ( - 1 / 18)(x^2 - 11x + 24) </span>
<span>y = (- 1 / 18)x^2 + (11 / 18)x - (3 / 2)
</span>
If this doesn't explain it enough, please, ask questions.
6 0
3 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
2 years ago
5 5/6 divided by 3 1/6
Elenna [48]

Answer:14-1/3 if that makes sense to you

Step-by-step explanation:

4 0
2 years ago
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