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3 years ago

Which property is demonstrated in the equation 0×25=0 ?

Mathematics

1 answer:

barxatty [35]3 years ago

8 0

Answer: “Zero Property of Multiplication” or “the Multiplication Property”

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Have three witches each holding a broom and a spoon. Witches say witch plus witch plus witch =45. Three brooms say broom plus br

GrogVix [38]

Answer:

a=43

Step-by-step explanation:

w+w+w= 45 which means 15+15+15=45

b+b+b=21 which means 7+7+7=21

s+s+s=12 which means 4+4+4=12

w+b×s= a which means 15+7×4= 43

(hope this helps)

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3 years ago

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Can a fraction that has 176/9 be simplified

maria [59]

No they cannot be simplified together from what I know

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3 years ago

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Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

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2 years ago

Solve 11x+10y=32..... Will mark the brainliest!

erica [24]

The equation 11x + 10y = 32 is a linear equation, and the solution to the linear equation 11x + 10y = 32 is $y = \frac{32 - 11x}{10}$

<h3>How to solve the equation?</h3>

The equation is given as:

11x + 10y = 32

Subtract 11x from both sides

10y = 32 - 11x

Divide both sides by 10

$y = \frac{32 - 11x}{10}$

Hence, the solution to the linear equation 11x + 10y = 32 is $y = \frac{32 - 11x}{10}$

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

4 0

1 year ago

some friends need 100 bows for a project Sara brings 12 bows Angela brings 50 bows and Nora brings 34 bows how many more bows do

Irina-Kira [14]

They need 4 more because 12+50+34=96 96-100 is 4 hope this helps ya

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3 years ago

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