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Anton [14]
4 years ago
6

How many liters of a 10% alcohol solution must be mixed with 90 liters of a 60% solution to get a 30% solution?

Mathematics
1 answer:
Setler [38]4 years ago
4 0
Since 10% = 0.10 by moving the decimal two spots to the left, we can say that 0.10L is the amount of alcohol with 10% concentration in L liters. Similarly, 0.60L is 60% for L liters and 0.30L is the amount of liters with 30%. If the amount of 10% alcohol solution in liters is x and the 60% in y, we get 0.10x+0.60y=0.30L due to that the liters add up to get a 30% amount of alcohol (this equation represents the amount of alcohol). Next, x+y=L. Since we know that we have 90 liters of 0.60, y=90 and we have 
0.10x+54=0.30L 
x+90=L. Plugging x+90 for L, we get 0.10x+54=0.3(x+90)=0.3x+27. Subtracting 27 and 0.1x from both sides, we get 0.2x=27. Next, we can multiply both sides by 5 (since 1/0.2=5) to get x=135 liters
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Answer:

<u><em></em></u>

  • <u><em>a. Meg needs to find the part</em></u>

<u><em></em></u>

  • <u><em>b. Steve needs to find the percent.</em></u>

<u><em></em></u>

Step-by-step explanation:

The question is incomplete.

This is the complete question:

<em>Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.</em>

<em />

<em>a. Does Meg need to find the part, the whole, or the percent.</em>

<em />

<em>b. Does Steve need to find the part, the whole, or the percent.</em>

<em />

<h2>Solution to the problem</h2>

<u><em>a. Does Meg need to find the part, the whole, or the percent.</em></u>

<em />

<em>Meg</em> already knows the <em>whole</em> and the <em>percent</em>.

The whole is the entire number of dogs seen: <em>16 dog</em>s.

The percent is <em>50%.</em>

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

  • Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

<u>b. Does Steve need to find the part, the whole, or the percent.</u>

<u></u>

He already knows <em>the part</em> (<em>7 of the 35 dogs were boxers</em>) and <em>the whole </em>(<em>35 dogs</em>).

Then he needs to find the percent, which he can do using the next operation:

  • Percent = (part / whole) × 100 = (7/35)×100 = 20%
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3 years ago
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5 0
3 years ago
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Watch help Video
Alexus [3.1K]

Answer: 5y − 1 + y^{2}

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below. Thank you!

<u>Step 1:</u><u> </u><u><em>Collect like terms.</em></u>

(3y + 2y) + (6 − 3 − 4) + (-6y^{2} + 7y^{2})

<u>Step 2: </u><u><em>Simplify.</em></u>

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~I hope I helped you! :) Good luck!~

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Answer:


Step-by-step explanation:

Left

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Right

The is another one where the work is hard to show. The numerator (m) of the fraction is the power and the denominator (n) is the root. That sentence is all the work there is.

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Answer:

Step-by-step explanation:

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