Answer:
Answer is 32
Step-by-step explanation:
Mode = no of stu +1/2
Mode =12+1/2
Mode =13/28=6.5
Mode =6th mark +7th mark /2
Mode=32+32/2
Mode=64/2
Mode=32
Hope it helps
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The equation of the line which passes through the point (-5, 3) and is parallel to the equation 3x -5y = 30 is; 3x -5y = 30.
<h3>What is the equation of the line?</h3>
Since the line is parallel to the given line; 3x -5y = 30 whose slope is; 3/5.
Hence, since the two lines have equal slopes;
3/5 = (y-3)/(x-(-5))
3/5 = (y-3)/(x+5)
5y -15 = 3x +15
3x -5y = 30
Read more on equation of a line;
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Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
Domain: All real numbers, except for x=4
Range: All real numbers
Step-by-step explanation:
There is no limit to how far either of the graphs go, so it will be infinite.
Given:
The sequence formula;
Tn = 4.5n - 8 (Where n = term number)
Required:
15th term = ?
Procedure:
All you need to do is use n = 15
T15 = 4.5(15) - 8
T15 = 59.5
Conclusion:
The 15th term of the sequence is 59.5.