Answer:
Helmut's basis at year-end is $3,900.
Explanation:
Beginning Basis = $2,000
Add: January 1 Liabilities at the rate of 10% = $20,000 × 10% = $2,000
Add: Increase in liabilities by the rate of 10% = $5,000 × 10% = $500
Less: Loss incurred at the rate of 10% = ($6,000 × 10%) = $600
Basis at the end of the year = $2,000 + $2,000 + $500 - $600
Basis at the end of the year = $3,900.
Answer:
Explanation:
Let x be the amount loaned at 7% and ($19,000 - x) be the amount loaned at 15%
Given:
Interest incurred at 7%, I1 + Interest incurred at 15%, I2 = $2000
Interest, I = amount × rate
I1 = 7/100 × x
I2 = 15/100 × ($19,000 - x)
From the above expressions,
(0.07)x + (0.15) × ($19,000 - x) = $2,000
Solving for x,
0.07x + 2850 - 0.15x = 2000
Collecting like terms,
0.08x = 850
x = $10625
The amount loaned at 7% interest is
$10625
The amount loaned at 15% interest is ($19000 - $10625)
= $8375
<span>Approximately 90% of all small businesses have no employees. These would be the businesses run by a single person or a partnership, with no outside help having been hired to help with the duties of the job. This shows that a great percentage of these businesses are one- and two-person endeavors, while the larger small businesses are a distinct minority.</span>
<span>The answer is : No coverage for xyx. Bob, an accountant of xyz, drives his own car to the bank to make a deposit for xyz. bob has an at-fault accident. if xyz carries $1,000,000 bodily injury/property damage coverage with a symbol 2 for covered autos, and bob carries no insurance, No coverage is applicable for xyz. </span>
Answer:
a) 15 to 35 approximately 95%
(b) 10 to 40 approximately almost all
(c) 20 to 30 approximately 68%
Explanation:
The data have a bell-shaped distribution which means the data is equally distributed on both sides of the mean.
We have the mean at 25 and a standard deviation of 5 which means that the interval is for each of the values of 5 .
The mean would be u and
The first value would be u ±σ = 25 ± 5= 20 and 30 (68 % )
The second value will be u ± 2σ= 25± 10 = 15 and 35 (95%)
The third value will be u ± 3σ= 25 ± 15 = 10 and 40 (99.7 % almost all)
In the figure below the light blue region gives u ±σ on both sides of the mean
, dark blue gives u ± 2σ values on both sides of the mean and grey gives
u ± 3 σ values on both sides of the mean.
It is obvious that 68 % of the data is contained in the u ±σ light blue region, 95 % of the data in the u ± 2σ dark blue including light blue and 99.7 % in the u ± 3σ all colored regions.
