Answer: room 101 and room 107
Step-by-step explanation:
In room 101, the ratio of boys to girls is 16:12. This is further simplified to its lowest fraction by dividing by 4. It becomes 4:3
In room 104, the ratio of boys to girls is 20:9. This cannot be further simplified to its lowest fraction.
In room 107, the ratio of boys to girls is 12:9. This is further simplified to its lowest fraction by dividing by 3. It becomes 4:3
Therefore, room 101 and room 107 have the same ratio.
Answer:
1/25
Step-by-step explanation:
substitute -2 where there are x
f(x) = 5^x
f(-2) = 5^(-2)
f(-2) = 1/(5^2)
f(-2) = 1/25
Answer:
2000
Step-by-step explanation:
sorry need points
The probability of selecting exactly one ace is its likelihood
The probability that a five-card poker hand contains exactly one ace is 29.95%
<h3>How to determine the probability?</h3>
There are 4 aces in a standard deck of 52 cards.
The probability of selecting an ace would be:
p = 4/52
Also, there are 48 non-ace cards in the standard deck
So, the probability of selecting a non-ace after an ace has been selected is:
p = 48/51
The probability of selecting a non-ace up to the fifth selection are:
- After two cards have been selected is: 47/50.
- After three cards have been selected is: 46/49.
- After four cards have been selected is: 45/48.
The required probability is then calculated as:
P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Where n is the number of cards i.e. 5
So, we have:
P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)
Evaluate
P(1 Ace) = 0.2995
Express as percentage
P(1 Ace) = 29.95%
Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%
Read more about probability at:
brainly.com/question/25870256
