the correct question is
The midpoint of kl is m(–8, 1). one endpoint is k(–6, 5). find the coordinates of the other endpoint l.
we know that
the formula of midpoint is
Xm=(x1+x2)/2----> 2*Xm=x1+x2------> x2=2*Xm-x1
Ym=(y1+y2)/2----> 2*Ym=y1+y2------> y2=2*Ym-y1
let
(x1,y1)-------> (–6, 5).
(Xm,Ym)-----> (-8,1)
find (x2,y2)
x2=2*Xm-x1-----> 2*(-8)-(-6)----> -10
y2=2*Ym-y1----> 2*(1)-5-----> -3
the point l is (-10,-3)
The answer isss..................... 69
The answer is A thanks for asking
Step-by-step explanation:
Derivation using Product rule : -
To find the derivative of f(x) = sin 2x by the product rule, we have to express sin 2x as the product of two functions. Using the double angle formula of sin, sin 2x = 2 sin x cos x. Let us assume that u = 2 sin x and v = cos x. Then u' = 2 cos x and v' = -sin x. By product rule,
f '(x) = uv' + vu'
= (2 sin x) (- sin x) + (cos x) (2 cos x)
= 2 (cos2x - sin2x)
= 2 cos 2x
This is because, by the double angle formula of cos, cos 2x = cos2x - sin2x.
Thus, derivation of sin 2x has been found by using the product rule.
