Please help! x+25=100

Kayla says that the point labeled C in the diagram below is the center. Raymond says that point C is the radius.

frutty [35]

Answer:

Kayla is correct The center is a fixed point in the middle of the sphere

Step-by-step explanation:

In mathematics we have certain habit of rules for notation of points, coordinates, segments, angles and so on.

Usually we denote points, by letters even more we denote with the first letter of the object we are denoting

Occasionally, we also denote segments as radius in a circle and in a sphere, with letters, that is r stands for radius, h stands for height, in most cases we denote point for capital letters ( in a segment)

When we denote radius, with small letter it should be placed at the center or over the segment we are traying to denote.

For points we only need to place the letter close to the to the point we want to denote.

Therefore Kayla is correct when says that c stand for " the center of the sphere"

8 0

3 years ago

Read 2 more answers

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

Select the correct answer what is the solution of 5/2x - 7 = 3/5x+14

bixtya [17]

Answer:

a i think

Step-by-step explanation:

4 0

2 years ago

Let f(x)=-2-7 and g(x)= -4x+6. Find (f*g)(-5)

Masja [62]

If (-5) = x then the anwser should be
-234

5 0

3 years ago

Don't really understand how to solve please help <3

valina [46]

This is how the first one would be done. sorry if it’s a little messy the answer is 9. but try using photomath for the rest. it gives you the answer and explains how to do it

8 0

3 years ago