Answer:
b option
Step-by-step explanation:
Refer to the attachment.
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Let:
x = cost of senior citizen ticket
y = cost of student ticket
4x + 5y = 102
7x + 5y = 126
4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4
7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4
note:
-35y/4 = -8.75y
714/4 = 178.5
-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14
x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8
x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea
This question seems to me to be an exercise in applying the rule for a difference of squares in order to rewrite the difference of two relatively large numbers as the "simpler" product of other integers.
Answer:
Distance cover by Alyson = 16 miles
Step-by-step explanation:
Given:
Distance cover together = 39 miles
Assume;
Distance cover by Jeff = a
Distance cover by Alyson = a - 7
Find:
Distance cover by Alyson
Computation:
a + (a - 7) = 39
2a - 7 = 39
2a = 46
a = 23
Distance cover by Alyson = a - 7
Distance cover by Alyson = 23 - 7
Distance cover by Alyson = 16 miles
