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IRISSAK [1]
3 years ago
12

The fastest commercially available rifle bullet claims a muzzle velocity of 4225 ft>s. (a) what is this speed in miles per ho

ur
Mathematics
1 answer:
galina1969 [7]3 years ago
8 0

Answer : 2880.68274  miles/hour

1 foot = 0.000189394 miles

4225 feet = 0.000189394* 4225 miles

distance traveled in 1 second =   0.000189394* 4225 miles

distance traveled in 1/3600 hours =   0.000189394* 4225 miles

distance traveled in 1 hour =   0.000189394* 4225 * 3600 miles

Speed is = 2880.68274 miles/hour

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Mixing the two ingredients would be adding them together:

1/2 gram + 3/4 gram = 1 1/4 total grams


Divide the total grams by 1/8 to find the number of experiments they can do:

1 1/4 / 1/8 = 5/4 / 1/8 = 5/4 * 8/1 = 40/4 = 10


They can conduct 10 experiments.


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3 years ago
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tekilochka [14]

Answer:

b is the answer

Step-by-step explanation:

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How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
2 years ago
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