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2 years ago

The triangle shown below has an area of 20 units. Find the missing side.

Mathematics

1 answer:

svlad2 [7]2 years ago

3 0

Yea there should be a picture to go with it so we can answer ur question

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Need help just 12 and 14 and answer choices

Lina20 [59]

12) First multiply 354 by 3.

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2 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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2 years ago

PLEASE HELP QUICK!! I NEED IT ASAP 6.

sukhopar [10]

Answer:

the answer C

Step-by-step explanation:

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2 years ago

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If x + 10 = 70, what is x? Α. 40 B. 50 C. 60 D. 70 E. 80

Helen [10]

Answer:

C.60

x + 10 = 70

x = 70 -10

x =60

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2 years ago

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A = {x | x is a positive, odd integer less than 7} -1

Lisa [10]

Answer

(5 2) (7 3) 2 3 5 x < x - - x - The inequality is 2 x < 5x 3 -2 – 7x 5 -3 Multiply ... Find all pair of consecutive odd positive integers both of which are smaller than 10 ... Let x be the smaller of the two odd positive integers so that the other is x + 2.

Step-by-step explanation:

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2 years ago